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C++ 编程:寻找矩阵的转置

为了理解这个示例,你应该具备以下 C++ 编程 主题的知识:

在这个程序中,用户被要求输入矩阵的行数和列数。在这个程序中,rowscolumns 的值应该小于 10。

然后,要求用户输入矩阵的元素。

程序计算矩阵的转置,并在屏幕上显示出来。

示例:寻找矩阵的转置

#include <iostream>
using namespace std;

int main() {
int a[10][10], transpose[10][10], row, column, i, j;

cout << "Enter rows and columns of matrix: ";
cin >> row >> column;

cout << "\nEnter elements of matrix: " << endl;

// 存储矩阵元素
for (int i = 0; i < row; ++i) {
for (int j = 0; j < column; ++j) {
cout << "Enter element a" << i + 1 << j + 1 << ": ";
cin >> a[i][j];
}
}

// 打印 a 矩阵
cout << "\nEntered Matrix: " << endl;
for (int i = 0; i < row; ++i) {
for (int j = 0; j < column; ++j) {
cout << " " << a[i][j];
if (j == column - 1)
cout << endl << endl;
}
}

// 计算矩阵的转置
for (int i = 0; i < row; ++i)
for (int j = 0; j < column; ++j) {
transpose[j][i] = a[i][j];
}

// 打印转置
cout << "\nTranspose of Matrix: " << endl;
for (int i = 0; i < column; ++i)
for (int j = 0; j < row; ++j) {
cout << " " << transpose[i][j];
if (j == row - 1)
cout << endl << endl;
}

return 0;
}

输出

Enter rows and columns of matrix: 2
3

Enter elements of matrix:
Enter element a11: 1
Enter element a12: 2
Enter element a13: 9
Enter element a21: 0
Enter element a22: 4
Enter element a23: 7

已输入的矩阵:
1 2 9

0 4 7


矩阵的转置:
1 0

2 4

9 7