C++ 编程:寻找矩阵的转置
为了理解这个示例,你应该具备以下 C++ 编程 主题的知识:
在这个程序中,用户被要求输入矩阵的行数和列数。在这个程序中,rows
和 columns
的值应该小于 10。
然后,要求用户输入矩阵的元素。
程序计算矩阵的转置,并在屏幕上显示出来。
示例:寻找矩阵的转置
#include <iostream>
using namespace std;
int main() {
int a[10][10], transpose[10][10], row, column, i, j;
cout << "Enter rows and columns of matrix: ";
cin >> row >> column;
cout << "\nEnter elements of matrix: " << endl;
// 存储矩阵元素
for (int i = 0; i < row; ++i) {
for (int j = 0; j < column; ++j) {
cout << "Enter element a" << i + 1 << j + 1 << ": ";
cin >> a[i][j];
}
}
// 打印 a 矩阵
cout << "\nEntered Matrix: " << endl;
for (int i = 0; i < row; ++i) {
for (int j = 0; j < column; ++j) {
cout << " " << a[i][j];
if (j == column - 1)
cout << endl << endl;
}
}
// 计算矩阵的转置
for (int i = 0; i < row; ++i)
for (int j = 0; j < column; ++j) {
transpose[j][i] = a[i][j];
}
// 打印转置
cout << "\nTranspose of Matrix: " << endl;
for (int i = 0; i < column; ++i)
for (int j = 0; j < row; ++j) {
cout << " " << transpose[i][j];
if (j == row - 1)
cout << endl << endl;
}
return 0;
}
输出
Enter rows and columns of matrix: 2
3
Enter elements of matrix:
Enter element a11: 1
Enter element a12: 2
Enter element a13: 9
Enter element a21: 0
Enter element a22: 4
Enter element a23: 7
已输入的矩阵:
1 2 9
0 4 7
矩阵的转置:
1 0
2 4
9 7